I've been trying to understand how ${x^3-12x+9}$ factors to $(x-3) (x^2+3 x-3)$ What factoring rule does this follow? The net result seems to be similar to what is attained through the sum/

5 The way to factor a four-term polynomial like this is to apply Rational Root Theorem along with synthetic division or substitution to determine whether a rational root works for the polynomial or not. …

Feb 28, 2016 · Proceed to factor the polynomial to find the other non-rational roots. I note that if you allow complex roots that are with many cube roots and other radicals, then all cubic polynomials and …

Aug 9, 2014 · I need to factor this in order to solve part of the problem but I was never taught how to factor polynomial with missing terms. I have tried using synthetic division and got $ (\lambda-1) (- …

Jan 7, 2018 · I am asking for detailed steps how to factor the cubic polynomial $${x^3-3x+2}$$ The solution is $${(x-1)^2(x+2)}$$

May 29, 2016 · The solution given is as follows: solution in Slader. Obviously, one cannot use synthetic division to factor our $ (2x +3)$ for the division works only for factors of the form $ (x-c)$. So my …

A cubic polynomial can only factor into the product of a linear and a quadratic factor (which itself might factor further). So if it has no linear factors, it's already irreducible.

Jul 17, 2021 · I'm okay at factoring some quadratics but this is cubic and I want to understand this one; it's driving me crazy. How did we get from the formula to the polynomial? BTW, I'm doing some …

I want to know how one would go about solving an unfactorable cubic. I know how to factor cubics to solve them, but I do not know what to do if I cannot factor it. For example, if I have to solve f...

Jul 5, 2015 · So in the worst case, you could try the possibilities $1,2,3,4,6,9,12,18,27,36,54,108$ as well as their negatives and then use polynomial long division when and if you find a root.